36. Graphs-2 (traversal problems)
1. No. of provinces
Count total components in a graph, using any traversal technique
-----------------------------------------------------------------------------------------------------------------------------2. Rotten oranges⭐
Multi source BFS
time: O(n*m) space: O(n*m)
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- count all fresh at start and then count if these many will rot in the process or not
- here we do not need a visited matrix since we can modify given
- we update time each time there rots atleast one orange in a BFS cycle
---------------------------------------------------------------------------------------------------------------------------- count all fresh at start and then count if these many will rot in the process or not
- here we do not need a visited matrix since we can modify given
- we update time each time there rots atleast one orange in a BFS cycle
3. No. of Islands
Count no. of islands (land surrounded by water in 4 directions)
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time: O(n^2) space: O(n^2)
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4. Flood Fill
BFS-
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5. No. of Enclaves
count no. of islands(group of 1s) where no land is on boundary
- set all 1s connected to boundary as 0, using multi source traversal
- count remaining 1s (lands) in entire matrix
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1. using BFS:
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2. using DFS:
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6. No. of distinct islands
we need to store shape of islands in a set and then return st.count()
In every dfs on an island, subtract base island coordinates from all neighbouring islands
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7. Surrounded regions
time: O(nm) space: O(nm)
- simply do a multi source BFS, on boundary 0s and preserve these by replacing with #s
- now replace all inner 0s with Xs
- now replace #s again with 0s
------------------------------------------------------------------------------------------------------------------------------ simply do a multi source BFS, on boundary 0s and preserve these by replacing with #s
- now replace all inner 0s with Xs
- now replace #s again with 0s
8. Dist of nearest cell having 0
we want to find distance of nearest 0s
so instead of doing BFS on every 1,
so instead of doing BFS on every 1,
we will use BFS on all 0s (multi source bfs)
jo koi bhi 0 kisi 1 ko pehle encounter krega toh us 1 ke liye vo wala 0 hi closest hoyega




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